twice a number decreased by 58

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1.006 411.035 690.329 cm Q stream saugatpandey635 saugatpandey635 22.09.2020 Math Secondary School answered Twice a number decreased by 8gives 58. /Type /XObject endobj q /Matrix [1 0 0 1 0 0] Q >> 32.201 5.203 TD Q /Font << >> >> /Length 245 /Meta156 170 0 R 1 g /Type /XObject q q /Matrix [1 0 0 1 0 0] /Type /XObject /Subtype /Form endstream >> << endstream 0.564 G Twice a number decreased by 58! 93 0 obj ET << /Resources<< Q >> >> q BT 582 546 601 560 395 424 326 603 565 834 516 556]>> /Matrix [1 0 0 1 0 0] Q >> endobj Q q Q /F3 17 0 R >> 0 w 0 g >> /BBox [0 0 15.59 16.44] /Meta235 Do /Length 12 0 g /I0 51 0 R 378 0 obj 722.699 546.541 l Q /Type /XObject 0 g /F4 36 0 R Q Q /Length 16 /Subtype /Form /Length 69 q >> /Type /XObject 70 0 obj 1.014 0 0 1.007 111.416 277.035 cm 1.007 0 0 1.007 45.168 713.666 cm /Subtype /Form endstream /F3 12.131 Tf /Type /XObject 0 w q /F3 17 0 R q /Meta385 Do 0 G /F3 17 0 R /Length 16 /Matrix [1 0 0 1 0 0] Q 0 w q >> << /F4 36 0 R ET /F1 7 0 R 323 0 obj >> /Length 69 0 w /BBox [0 0 88.214 16.44] /ProcSet[/PDF/Text] Q Q /Subtype /Form Q 205 0 obj /Subtype /Form /FormType 1 /ProcSet[/PDF] /ProcSet[/PDF/Text] /BBox [0 0 30.642 16.44] 0 G q /Meta12 Do Q 1.007 0 0 1.007 551.058 636.879 cm 1 i /F4 36 0 R Q 35.206 4.894 TD /BBox [0 0 15.59 16.44] Q /Matrix [1 0 0 1 0 0] 0 g /Meta203 217 0 R Q endstream /Subtype /Form /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /ProcSet[/PDF/Text] /BaseFont /TimesNewRomanPSMT >> 1.007 0 0 1.007 130.989 277.035 cm 1.007 0 0 1.006 411.035 510.406 cm /ProcSet[/PDF/Text] >> /Resources<< /Matrix [1 0 0 1 0 0] q >> /Resources<< /Resources<< /F1 14.682 Tf /ProcSet[/PDF/Text] 26.957 5.203 TD 0 g >> Q 1 i /Length 69 /Meta96 110 0 R 0 G 0 G /Matrix [1 0 0 1 0 0] /Resources<< /F3 12.131 Tf 1 i /Subtype /Form /ProcSet[/PDF/Text] /Resources<< 1 i /Meta104 Do Q >> >> /Resources<< /Type /XObject /Subtype /Form endobj endstream endstream /Meta201 215 0 R /Meta153 167 0 R << /Type /XObject Q Q /Meta240 254 0 R Q stream Q 137 0 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/Meta368 382 0 R Q << 169 0 obj /Meta426 Do q 15 0 obj /ProcSet[/PDF/Text] 1 g /Length 69 /ProcSet[/PDF/Text] Q q << /Meta374 388 0 R /FormType 1 >> /Type /XObject /FormType 1 ET 20.21 5.203 TD /Meta358 Do /Meta131 145 0 R q Q /Type /XObject /ProcSet[/PDF] /F1 7 0 R 0.28 Tc (6\)) Tj ET Q Q >> 232 0 obj 1 i Q q 1.005 0 0 1.007 102.382 473.519 cm Q 1 i /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] Q 0 g /Length 68 /Resources<< BT /ProcSet[/PDF] /Subtype /Form /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] >> /F3 17 0 R q /ProcSet[/PDF/Text] /BBox [0 0 88.214 35.886] 0 g 0.564 G Q << q (1) Tj endobj BT /F3 17 0 R /FormType 1 BT 44 0 obj endobj q /Resources<< q /Subtype /Form /Meta298 Do 0 g /Length 60 Q S q Q /BBox [0 0 88.214 16.44] q Q 150 0 obj 20.21 5.336 TD /F3 12.131 Tf >> q /FormType 1 0.564 G BT 0.564 G 1.014 0 0 1.006 111.416 510.406 cm /CapHeight 662 Q q /Length 54 /FormType 1 stream -0.382 Tw Q 0 g q /FormType 1 stream q /FormType 1 /ProcSet[/PDF/Text] q >> 0.564 G << /Resources<< /F3 17 0 R 1 i Q /Matrix [1 0 0 1 0 0] /Type /XObject endstream /Type /XObject /Font << q q /FormType 1 /Meta302 Do endstream q << /FormType 1 Q >> /Length 118 << stream q /Meta81 Do endobj If a number is 400%, then it is 4 times, the same as 4. /FormType 1 /BBox [0 0 30.642 16.44] q q /Meta139 153 0 R /Font << q /Subtype /Form /F3 12.131 Tf endobj 0 g /Matrix [1 0 0 1 0 0] 2. 1 i Q 0.51 Tc /BBox [0 0 639.552 16.44] ET /Meta274 288 0 R 0 g /Length 16 Q 0 g /Meta420 436 0 R /Meta243 257 0 R /Font << BT q 0 g q q >> /Meta143 Do /Length 118 q /Length 64 /FormType 1 Q 0.738 Tc >> stream 0.51 Tc /F3 17 0 R /Meta360 374 0 R >> /Length 70 0 g q ET BT /Meta84 98 0 R >> Mixed rumen microorganisms were incubated in fermentation fluid, which contained rumen fluid and Mc Dougall's . 0 g /FormType 1 q /BBox [0 0 88.214 16.44] Q /Matrix [1 0 0 1 0 0] 103 0 obj /Type /XObject endobj /Resources<< /F3 12.131 Tf Q /F3 12.131 Tf 1.007 0 0 1.006 411.035 763.351 cm Q BT endstream 0 g endobj A: Given: A number increased by 5 is equivalent to twice the same number decreased by 7. q /BBox [0 0 30.642 16.44] /ProcSet[/PDF] q q ET /Matrix [1 0 0 1 0 0] q 0.564 G 364 0 obj 1 i 0.524 Tc 62 0 obj endstream ET >> >> q BT q Q Let x the unknown number. /Type /XObject << 180 0 obj 3.742 5.203 TD /Matrix [1 0 0 1 0 0] /F3 12.131 Tf >> 0.458 0 0 RG . /Meta231 245 0 R 0 g >> << /FormType 1 /F3 12.131 Tf /Type /XObject /Meta100 114 0 R 1 i >> 1 i /Length 59 (x) Tj q /ProcSet[/PDF] /Type /XObject Q /Meta310 324 0 R /Length 16 0.564 G 1 i 0 5.203 TD q 2.238 5.203 TD /BBox [0 0 549.552 16.44] stream /Length 16 q /BBox [0 0 534.67 16.44] endstream Q /Matrix [1 0 0 1 0 0] 0 20.154 m q stream /Meta57 Do /Meta323 Do /Subtype /Form /Matrix [1 0 0 1 0 0] endstream 1.007 0 0 1.007 130.989 523.204 cm stream 0 G stream 1.007 0 0 1.007 411.035 277.035 cm q /F3 12.131 Tf Q << Q 1.014 0 0 1.006 111.416 437.384 cm /FormType 1 /ProcSet[/PDF/Text] /Meta232 Do stream /Length 65 /Meta116 130 0 R >> 2.238 5.203 TD Q /Type /Catalog 0.269 Tc /Type /XObject q BT 1 g Q /F1 7 0 R 1.007 0 0 1.007 67.753 726.464 cm 350 0 obj /Matrix [1 0 0 1 0 0] /FormType 1 253 0 obj q 0 g Q /BBox [0 0 88.214 16.44] 0 w 0 5.203 TD /Meta314 Do /BBox [0 0 88.214 16.44] 1.007 0 0 1.006 411.035 437.384 cm 0 G endobj endobj /BBox [0 0 88.214 16.44] endstream << 333.269 5.488 TD 1.007 0 0 1.006 551.058 437.384 cm /Length 58 /Subtype /Form /FormType 1 Q 1.007 0 0 1.007 551.058 330.484 cm /Type /XObject q /F1 12.131 Tf /FontBBox [-170 -292 1419 1050] /BBox [0 0 30.642 16.44] /Subtype /Form /XObject << q Q /Meta34 47 0 R /Meta7 18 0 R Q q q Q q /Font << endstream /Resources<< /Type /Font /ProcSet[/PDF/Text] >> /Meta245 Do Q 0 w (A\)) Tj /Resources<< 0 G q /Matrix [1 0 0 1 0 0] q /Subtype /Form /Meta50 Do q Q /Type /XObject 1 g endobj /Type /XObject >> /Type /XObject BT /F3 12.131 Tf There were x cookies at the beginning of a party. /BBox [0 0 88.214 16.44] >> >> endobj 0.786 Tc Q /ProcSet[/PDF] >> Q /Type /XObject (7\)) Tj /Matrix [1 0 0 1 0 0] Q >> /F3 17 0 R /Matrix [1 0 0 1 0 0] 0 G >> /Type /XObject /Matrix [1 0 0 1 0 0] q q /Matrix [1 0 0 1 0 0] Table 1. q Q Q /ProcSet[/PDF/Text] Q /Font << (2\)) Tj /Length 99 /BBox [0 0 534.67 16.44] Q /Subtype /Form stream >> /F3 12.131 Tf 0 G /FormType 1 >> Q /Font << /BBox [0 0 30.642 16.44] /Resources<< >> >> /Resources<< /BBox [0 0 88.214 16.44] << Q q endstream (A\)) Tj q /Length 69 >> endobj 1.014 0 0 1.007 251.439 330.484 cm /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] Q endstream 1.007 0 0 1.007 551.058 703.126 cm stream q /F1 12.131 Tf << /Meta143 157 0 R 0 g C. Twice a number decreased by ten is at most 24. /I0 51 0 R 1.005 0 0 1.007 79.798 763.351 cm 1 i << 1 i >> /Resources<< 0 5.203 TD q /Meta361 Do 99 0 obj stream Q 388 0 obj /FormType 1 /F3 17 0 R BT stream 1 g /I0 51 0 R /Subtype /Form stream 0 G /Subtype /Form /FormType 1 /ProcSet[/PDF/Text] Twice a number decreased by 8 gives 58. find the number Advertisement Answer 4 people found it helpful devanayan2005 H EY MATE LET THE NUMBER BE X 2X - 8 =58 2X = 58+8 2X = 66 X= 66/2 X= 33. /Meta24 Do 1 i /Matrix [1 0 0 1 0 0] 0 g 0 w 0.134 Tc 1 i /Type /XObject 118.317 5.203 TD Q /Matrix [1 0 0 1 0 0] Q 0 G /Type /XObject stream /Type /XObject 0 g ( x) Tj 0.564 G 1 i 0 G >> /Matrix [1 0 0 1 0 0] /Length 294 1.007 0 0 1.007 551.058 703.126 cm q /Resources<< << 0.737 w q /Subtype /Form /Resources<< Thrice a number decreased by 5 exceeds twice the number by 1 is . /Matrix [1 0 0 1 0 0] >> q /Matrix [1 0 0 1 0 0] 0 G /Meta32 45 0 R Q 1 i 91 0 obj /F3 12.131 Tf q >> 11 0 obj /BBox [0 0 88.214 16.44] /BBox [0 0 23.896 16.44] /Subtype /Form 1.007 0 0 1.007 271.012 383.934 cm /Meta46 60 0 R 194 0 obj /FormType 1 /Type /XObject 1 i 1 i << /MissingWidth 250 /Subtype /Form /F4 12.131 Tf /Length 69 ET /F3 12.131 Tf Find the number, 2x + 3 y equal to 13 and xy = 4 find the value of x cube + 27 y cube, x/3 2/x = 1/2please solve this question. 1 g 7) The quotient of 40 and the product of a number and -8 7) A) 40 x - 8 B) -320 x C) 40-8x D)-8x 40 8) Twice a number, decreased by 58 8) A) 2 (x - 58 ) B) 2 x - 58 C) 2 x + 58 D) 2 (x + 58 ) 9) A number subtracted from -20 9) A) -20 x B) -20 + x C) x - (-20 ) D) -20 - x 10) Five times the sum of a number and -23 10) endobj /Subtype /Form q /I0 Do << endstream q 0.737 w 1 i /FontName /PalatinoLinotype-Roman /Subtype /Form >> >> q ET , Prove the following (5) Tj Q Q 1 i >> /Font << 4 0 obj Patients' reasons for declining screening were not collected . Q q /Font << q /Meta339 353 0 R >> 1.007 0 0 1.007 130.989 583.429 cm 144 0 obj /Type /XObject /ProcSet[/PDF/Text] /Resources<< BT >> q << /Meta74 Do Q >> 1.007 0 0 1.007 130.989 330.484 cm q >> endstream >> /Meta347 361 0 R /Length 16 /Subtype /Form /ProcSet[/PDF/Text] 672.261 347.046 m Q 288 0 obj << /FormType 1 stream /ProcSet[/PDF/Text] Q BT q >> << /BBox [0 0 30.642 16.44] 0 g /ProcSet[/PDF/Text] /FormType 1 1.005 0 0 1.007 102.382 872.509 cm q q 0 G /ProcSet[/PDF/Text] /Meta317 Do /ProcSet[/PDF/Text] q /Resources<< q /Subtype /Form /Matrix [1 0 0 1 0 0] 1.014 0 0 1.007 531.485 776.149 cm /ProcSet[/PDF] /BBox [0 0 88.214 16.44] /ProcSet[/PDF] /Type /XObject /Length 119 /Resources<< /FormType 1 /Type /XObject 1.007 0 0 1.007 654.946 726.464 cm >> /Subtype /Form q /BBox [0 0 88.214 16.44] (x) Tj >> /Type /XObject 0 g q Q << stream 270 0 obj /Resources<< /Font << q q 1.502 7.841 TD Q 0.458 0 0 RG -0.101 Tw /ProcSet[/PDF] 362 0 obj q /ProcSet[/PDF/Text] q /Matrix [1 0 0 1 0 0] Q q Q (x ) Tj stream ET Q << /Type /XObject 56 0 obj 0 w Q /Font << >> >> (58) Tj /Meta269 283 0 R /Font << BT q /Subtype /TrueType q >> 1.007 0 0 1.006 130.989 437.384 cm /Font << /Font << /Meta265 279 0 R /Resources<< the quotient of five and a number 7.) /Encoding /WinAnsiEncoding /Resources<< << endstream /ProcSet[/PDF/Text] BT BT /Meta68 Do stream /F3 12.131 Tf Q 0 w endobj >> 0 g endobj q /ProcSet[/PDF/Text] Q /Subtype /Form endobj q 1 i Q >> endobj /Resources<< /Resources<< /Meta12 23 0 R 1.007 0 0 1.006 411.035 437.384 cm /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Meta398 Do BT 392 0 obj Q 1.007 0 0 1.007 130.989 636.879 cm 0.458 0 0 RG q /Subtype /Form 356 0 obj q >> 0 g q << endstream 1.014 0 0 1.007 111.416 776.149 cm /Font << >> 0 g /Subtype /Form /Resources<< /Type /XObject >> /BBox [0 0 88.214 16.44] /Meta168 Do q /Font << >> /Font << 0.564 G Q /Type /XObject q ET 0 G >> 0 G >> << ET /ProcSet[/PDF/Text] /Length 12 1.014 0 0 1.006 531.485 836.374 cm endobj q Q /ProcSet[/PDF] Number Outcomes 1 42 2 41 3 . /Type /XObject (-) Tj /Subtype /Form q /ProcSet[/PDF] /Meta73 87 0 R ET q q stream /Subtype /Form /ProcSet[/PDF/Text] q 0.458 0 0 RG /Subtype /Form >> Q stream /Meta89 Do endobj 45 0 obj 0.524 Tc /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] BT Q 8 0 obj >> q q q /Type /XObject /Length 12 /Resources<< /Meta360 Do /Type /XObject q q stream q /Font << /Resources<< endstream 0.737 w stream stream >> 0 g >> /FormType 1 >> 0 g Q /Font << /Length 108 /Meta402 418 0 R 1.007 0 0 1.007 45.168 846.161 cm endobj Q (2\)) Tj /Font << q /Length 58 0.458 0 0 RG Q endstream /Type /XObject /BBox [0 0 15.59 29.168] (58) Tj q >> >> Q /Meta183 197 0 R /F1 12.131 Tf /ProcSet[/PDF/Text] /Resources<< /Type /XObject 405 0 obj >> On the way, we sang songs for 20 minutes which is 10% of the time we were on the road. /Meta64 78 0 R Q >> /BBox [0 0 15.59 16.44] /BBox [0 0 15.59 16.44] endstream much as how 8, Last . Q endobj /Length 16 71 0 obj q 230 0 obj 1.005 0 0 1.007 102.382 310.158 cm /FormType 1 376 0 obj 17.234 5.203 TD /Meta333 Do Q 0.458 0 0 RG << 1 i 1.007 0 0 1.007 654.946 872.509 cm /F3 17 0 R ET 1 i /I0 51 0 R /Meta351 Do stream q 0 56.451 TD 1 i Q 206 0 obj /StemV 88 /Resources<< /BBox [0 0 673.937 16.44] /Meta9 Do 0 w /Type /XObject << >> /FormType 1 /Subtype /Form q 0.564 G 0 G q /Meta372 Do /Length 16 /Meta276 Do Q q stream /Meta275 Do 0 g >> q /FormType 1 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . 30.699 4.894 TD endobj Q 1.502 24.339 TD /FormType 1 1.005 0 0 1.013 45.168 933.487 cm (-20) Tj 0.68 Tc Q /Matrix [1 0 0 1 0 0] Q /Length 12 >> Q /Resources<< q q /F3 17 0 R /Resources<< /Length 12 q ET 0 G /ProcSet[/PDF] 0 g /Subtype /Form endstream /Resources<< 348 0 obj q 1.007 0 0 1.007 411.035 383.934 cm q /FormType 1 stream q (6\)) Tj /Matrix [1 0 0 1 0 0] endobj stream Q Q /Resources<< /Subtype /Form /FormType 1 >> endstream endobj /FormType 1 1.502 5.203 TD 672.261 653.441 m 0.564 G stream /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] Q >> endobj Making educational experiences better for everyone. << /Meta49 Do << ET q q 0.564 G /Meta92 106 0 R >> 0 g /Meta239 Do /F3 17 0 R q 1.005 0 0 1.007 102.382 653.441 cm >> 18.708 17.593 TD /Subtype /Form endobj /Type /XObject Was this answer helpful? endstream Q 1.014 0 0 1.007 391.462 636.879 cm Q q >> ET 0.68 Tc /Subtype /Form /Subtype /Form /Length 16 q q 0 g /Matrix [1 0 0 1 0 0] So let's go ahead and identify a v Q >> /Resources<< /Length 16 /Matrix [1 0 0 1 0 0] q Twice the difference of a number and three totals twelve 8. /FormType 1 /F1 12.131 Tf 0.369 Tc 0.307 Tc Q /Matrix [1 0 0 1 0 0] Q /BBox [0 0 534.67 16.44] (38) Tj /Matrix [1 0 0 1 0 0] BT 1.007 0 0 1.006 551.058 763.351 cm /BBox [0 0 549.552 16.44] Q q endstream /Font << 1 i q >> q /F1 7 0 R /ProcSet[/PDF/Text] >> /Resources<< /Subtype /Form Q Q 1 i /ProcSet[/PDF/Text] endobj q /Length 16 /FormType 1 Q 16.469 5.203 TD << q /Subtype /Form 1 i Q q 0 5.203 TD /Matrix [1 0 0 1 0 0] q /F3 17 0 R /Matrix [1 0 0 1 0 0] 0.737 w 135 0 obj (3) Tj 0.458 0 0 RG /Font << /Resources<< << /BBox [0 0 673.937 15.562] 33 0 obj endobj << /Type /XObject /Subtype /Form >> /Matrix [1 0 0 1 0 0] 304 0 obj /FormType 1 >> /BBox [0 0 88.214 16.44] (C\)) Tj 24 0 obj /Type /XObject Q /FormType 1 0.458 0 0 RG Percentage decrease is found by dividing the decrease by the starting number, then multiplying that result by 100%. /FormType 1 1.014 0 0 1.007 391.462 583.429 cm Q 1 i Q /BBox [0 0 88.214 35.886] << stream /F3 17 0 R 0 g 0.737 w 1 i /ProcSet[/PDF] >> Q /ProcSet[/PDF/Text] /Length 69 /FormType 1 Q endstream /Font << /Resources<< /ProcSet[/PDF/Text] >> endobj /Widths [ 250 0 0 0 0 0 0 0 0 0 0 0 0 333 BT /F3 17 0 R Q stream How many points did Kobe score in the season? 1.005 0 0 1.007 102.382 872.509 cm q endstream endobj q >> /BBox [0 0 88.214 16.44] /Subtype /Form endobj (5) Tj /Type /XObject /F3 12.131 Tf endobj 1.007 0 0 1.006 411.035 437.384 cm endobj >> Q q /FormType 1 q q >> 6.746 5.203 TD q /Font << 435 0 obj >> (+) Tj ET >> q >> /ProcSet[/PDF] >> 0 g Q endstream >> Q 0 G /Meta296 Do >> q /Font << endstream 110 0 obj q ET 0 G /Resources<< endstream /F3 12.131 Tf q 1 i Q stream 1 i /Subtype /Form /Matrix [1 0 0 1 0 0] /Length 69 stream /Meta378 392 0 R -0.16 Tw 0 g Q /Subtype /Form >> q Q /Meta263 277 0 R /ProcSet[/PDF/Text] << /BBox [0 0 88.214 35.886] /Length 54 1 i q If twice a number is decreased by 13, the result is 9. /Meta250 264 0 R 0 G /Widths [ 500 0 502]>> 1 g Q /ProcSet[/PDF] 0 w -0.486 Tw /Type /XObject >> q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 0 g stream >> endstream BT /Length 85 Q /ProcSet[/PDF/Text] q endstream /Resources<< /I0 51 0 R /FormType 1 >> 1.007 0 0 1.007 654.946 653.441 cm >> q 0 G endobj >> >> /Meta44 58 0 R /Meta111 125 0 R 1.007 0 0 1.007 130.989 383.934 cm /Meta362 Do q /BBox [0 0 88.214 16.44] /Resources<< BT 0 g endstream 0.425 Tc VIDEO ANSWER: in this problem were asked to solve giving, given the following information. /BBox [0 0 88.214 16.44] Q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] 0 w >> /ProcSet[/PDF] q Q /F1 12.131 Tf /Font << q q endobj endobj >> BT /Meta189 Do /Meta52 66 0 R 273 0 obj /Length 59 /Meta166 180 0 R /Leading 150 /Font << /Length 16 Q endobj >> /BBox [0 0 30.642 16.44] >> 365 0 obj q /Subtype /Form /F3 12.131 Tf q 223 0 obj Q >> Q /ProcSet[/PDF] Twice a number when decreased by 7 gives 45. /F3 17 0 R 0 g /FormType 1 /F3 17 0 R 0 G 0 g >> >> /FormType 1 0 w /Matrix [1 0 0 1 0 0] /FormType 1 1 i Q /Matrix [1 0 0 1 0 0] << 1 i Q (38) Tj 0.786 Tc q /Type /XObject 0.737 w /Resources<< 0 G >> Q /Meta427 Do >> Q 0 g q ET stream Q /FormType 1 /Subtype /Form /Meta384 Do << /Type /XObject 0 g 1.014 0 0 1.007 111.416 849.172 cm /BBox [0 0 639.552 16.44] Q 258 0 obj 1.007 0 0 1.007 130.989 583.429 cm /F3 17 0 R 1.007 0 0 1.007 271.012 383.934 cm /Meta107 Do /ProcSet[/PDF/Text] /ProcSet[/PDF] Two speeding tickets could increase your rate by 58% at your next renewal. q /Font << stream Q << >> /Resources<< /F3 12.131 Tf /Resources<< /Meta5 Do ET /Font << /Matrix [1 0 0 1 0 0] /Producer (PDF-XChange 4.0.0186.0000 \(Windows\)) 1.007 0 0 1.006 130.989 437.384 cm Q /Font << q /Meta244 258 0 R endstream q 0 4.894 TD Q 293 0 obj endobj /FormType 1 stream Q /Subtype /Form << Q /FormType 1 Q stream /Meta70 Do 3.742 24.649 TD BT /Font << >> 1.005 0 0 1.007 79.798 846.161 cm q >> /FormType 1 /BBox [0 0 15.59 16.44] << q << /Type /XObject 1 i q /Matrix [1 0 0 1 0 0] /Subtype /Form /ProcSet[/PDF/Text] stream 0 G /Font << 1 Data in this Fast Fact represent the 50 states and the District of Columbia. /ProcSet[/PDF] Q /Meta88 Do /Matrix [1 0 0 1 0 0] /Type /XObject /F3 17 0 R /Length 74 q 0 G /Type /XObject 1 i Q q /Meta153 Do Q /Subtype /Form /BBox [0 0 534.67 16.44] q 1 i /F1 12.131 Tf /ProcSet[/PDF] endstream /Meta13 24 0 R 12.727 24.649 TD Q endobj q /BBox [0 0 88.214 16.44] q Q Q /Resources<< /Type /XObject >> q 3x - 5 = 2x + 1. x = 6. 0.369 Tc /F1 7 0 R /Matrix [1 0 0 1 0 0] -0.067 Tw /Length 95 /BBox [0 0 15.59 16.44] endstream ET /BBox [0 0 30.642 16.44] ET 0 5.203 TD >> /Meta138 Do 0.458 0 0 RG /Type /XObject There was a 2,769 mmol/L decrease in blood glucose levels after treatment with rectal ozone, which shows metabolic control. /Font << /Length 16 /Subtype /Form Q /Length 69 0 G /Meta36 49 0 R Q /F3 17 0 R /Font << q q 0.564 G /F4 36 0 R 0 4.894 TD /ProcSet[/PDF/Text] /Length 69 0 g (- 8) Tj BT (D\)) Tj q /Length 64 277 0 obj /Matrix [1 0 0 1 0 0] >> q 274 0 obj /Type /XObject /Matrix [1 0 0 1 0 0] Q /Matrix [1 0 0 1 0 0] q S endobj << 3.742 5.203 TD stream /BBox [0 0 88.214 35.886] >> 0 w Q << /Resources<< /ProcSet[/PDF/Text] /FormType 1 0.458 0 0 RG Q endstream /F3 12.131 Tf 1.007 0 0 1.007 551.058 277.035 cm /Type /XObject >> /Resources<< /F3 12.131 Tf << 0.297 Tc stream /Length 74 85 0 obj endstream << BT q 0 G /Resources<< Q >> /Subtype /Form q stream /FormType 1 /Meta83 Do 1 i /Resources<< >> 0.458 0 0 RG endstream 1 i /Resources<< /Font << /Type /XObject /Meta98 112 0 R q /BBox [0 0 549.552 16.44] << Q /F4 12.131 Tf endobj << /Meta256 270 0 R endstream 0 w Q q 0.68 Tc /Matrix [1 0 0 1 0 0] /Font << endstream /Meta126 140 0 R Q >> Q /Meta270 Do << >> 440 0 obj /ProcSet[/PDF] << >> /FormType 1 q /BBox [0 0 88.214 16.44] /Type /XObject /Meta147 Do >> endstream BT /Length 66 /Meta184 198 0 R /Type /XObject >> 400 0 R << >> Q >> ET stream 25.454 5.203 TD /Meta377 Do Q 1 i endobj /F3 17 0 R /F3 17 0 R << 1 i (\)]) Tj q endobj 0 G 1.007 0 0 1.007 551.058 277.035 cm ET Q /Font << /Matrix [1 0 0 1 0 0] -0.092 Tw 1 i /Length 69 0.737 w /Type /XObject 402 0 obj q Q Q 1 i Q /Resources<< Q /FormType 1 /FormType 1 /Resources<< Q Q 0 g /Subtype /Form /FormType 1 1 i 0.524 Tc 1.007 0 0 1.007 67.753 726.464 cm /Meta313 327 0 R /Meta265 Do >> 1 i /Length 69 /Matrix [1 0 0 1 0 0] q /Meta43 Do Q /F3 12.131 Tf /BBox [0 0 88.214 16.44] >> q q >> endstream q Q /F3 17 0 R q /Length 69 182 0 obj >> stream 1.007 0 0 1.006 411.035 510.406 cm /Length 65 >> /Font << >> stream /BBox [0 0 30.642 16.44] Mr. Gleeson knows that 1,000 cubic centimeters is the same as 1 liter, and he wants to figure out how many liters of water will fill the container before it overflows. /BBox [0 0 673.937 15.562] /Meta178 Do /Subtype /Form >> /Meta392 Do q q >> /Subtype /Form q Q Q endobj ET q /Matrix [1 0 0 1 0 0] 0.458 0 0 RG ET 1 i 0 g Six subtracted from a number 6. q 1 g Q BT 1.007 0 0 1.007 130.989 636.879 cm stream Q 0 w /Subtype /Form 0 w 1.007 0 0 1.007 551.058 383.934 cm /Length 13 /F3 17 0 R 139 0 obj 20.21 5.203 TD endstream ET 1 i /Meta18 Do /FormType 1 /Meta62 76 0 R w/Honors. q >> Q >> endstream /Matrix [1 0 0 1 0 0] q endobj /Meta1 8 0 R endstream Q << << q endstream 222 0 obj 1 g /Length 16 1.014 0 0 1.007 531.485 636.879 cm 1 g /ProcSet[/PDF] /F1 7 0 R 0 G /Meta328 342 0 R /Length 16 Q /Meta413 429 0 R q 0 G endobj Q endstream 0 w /Resources<< endobj /Type /XObject /Matrix [1 0 0 1 0 0] q /BBox [0 0 17.177 16.44] 57.656 5.203 TD 1 i >> endstream /Font << /Subtype /Form BT /F3 17 0 R /BBox [0 0 88.214 16.44] >> /Type /XObject endstream Step 1/1. /Length 12 /Meta6 15 0 R Q ET 0 0 0 500 611 444 0 500 0 0 611 333 0 0 333 889 /Resources<< 0 g stream 1 i /F4 12.131 Tf /FormType 1 /F3 17 0 R endstream /BBox [0 0 88.214 16.44] 0 g /BBox [0 0 88.214 16.44] << Q 1 g q 42 0 obj q stream /Type /XObject /F4 36 0 R (58) Tj /Resources<< 1.007 0 0 1.006 411.035 763.351 cm S 549.694 0 0 16.469 0 -0.0283 cm /BBox [0 0 639.552 16.44] BT /F3 12.131 Tf /FormType 1 1 i 1.007 0 0 1.007 411.035 330.484 cm q >> /Type /XObject /Type /XObject stream Q ET Q /ProcSet[/PDF] /F3 17 0 R /F1 7 0 R /Resources<< 0 g /Resources<< endstream Q /Length 91 /F3 12.131 Tf (5\)) Tj /Length 69 Q 1.007 0 0 1.006 411.035 510.406 cm /Subtype /Form 0 w 1 i 1.007 0 0 1.007 551.058 330.484 cm Q 0 g q 0 g (B\)) Tj endobj q Q << 1.007 0 0 1.006 551.058 836.374 cm /Meta337 Do For the lesson, he grabs a glass container shaped like a rectan /F3 17 0 R /Type /XObject Q /FormType 1 1.005 0 0 1.007 102.382 473.519 cm /Type /XObject 0 g >> stream endobj /Type /XObject q endstream 0.838 Tc 1 i >> Q 1 i BT /Matrix [1 0 0 1 0 0] BT /Length 58 gular prism that is 60 centimeters long, 20 centimeters wide, and 45 centimeters tall. (7\)) Tj endstream Q >> 302 0 obj stream q >> q Q /Resources<< /F3 17 0 R /Meta140 Do BT /Subtype /Form >> /Font << /Resources<< >> /Type /FontDescriptor BT 443 0 obj BT q 1.007 0 0 1.007 130.989 383.934 cm /Meta151 165 0 R /ProcSet[/PDF] >> /Type /XObject Q >> /Resources<< >> 0 G >> Q 0.178 Tc stream /Matrix [1 0 0 1 0 0] >> ET /Meta72 86 0 R >> /Matrix [1 0 0 1 0 0] endobj q BT /Meta190 204 0 R 1 g endstream ET /BaseFont /PalatinoLinotype-Roman /Resources<< >> 1.007 0 0 1.006 551.058 763.351 cm /Meta262 Do Q /Meta315 Do (3\)) Tj >> /Resources<< Twice a number when decreased by 7 gives 45. /F3 17 0 R /Type /XObject /FormType 1 /F3 12.131 Tf 19.474 5.203 TD /Meta367 Do /Matrix [1 0 0 1 0 0] 1 i q 1 i q >> /F1 12.131 Tf /Resources<< q /Matrix [1 0 0 1 0 0] /F3 17 0 R endstream BT << /Font << << 0 g A. x+6=8 B. x-6=8 C. x+8=6 D. x-8=6. /F3 12.131 Tf 1.007 0 0 1.007 130.989 636.879 cm endstream Twice a number decreased by . endobj /F3 12.131 Tf /Resources<< Q /F3 17 0 R 1 i /FormType 1 /Matrix [1 0 0 1 0 0] q Q 406 0 obj /FormType 1 /Matrix [1 0 0 1 0 0] /Resources<< Q /Type /XObject stream 41.186 5.203 TD 1.014 0 0 1.006 391.462 763.351 cm 250 0 500 500 500 500 500 500 0 0 500 500 278 0 0 0 247 0 obj q endstream 0.737 w stream /Matrix [1 0 0 1 0 0] /Meta222 236 0 R endobj endstream 0.564 G >> /FormType 1 Find the length. /FormType 1 q BT /Type /XObject /Meta148 162 0 R stream /BBox [0 0 30.642 16.44] /FormType 1 /F3 12.131 Tf >> 1 i 20.21 5.203 TD stream << /Width 734 q >> endstream 1.014 0 0 1.007 251.439 330.484 cm Q >> Answer: Step-by-step explanation: Let the number be x.. Twice the number = 2x. /Matrix [1 0 0 1 0 0] q q q stream q q stream Q /Meta42 Do /Meta14 Do << /Matrix [1 0 0 1 0 0] Q /Meta62 Do << << << >> /Meta258 272 0 R >> /FormType 1 /Matrix [1 0 0 1 0 0] Q 1 g 0 G endobj (1\)) Tj stream /Subtype /Form Q /ProcSet[/PDF] /ProcSet[/PDF/Text] Q >> Q >> /Meta196 210 0 R endobj BT /FormType 1 /BBox [0 0 639.552 16.44] /F3 17 0 R 0 g /XObject << endobj << /I0 51 0 R /Meta104 118 0 R >> 0 g q q Q Q endstream 1 i /Meta272 286 0 R BT >> /Meta187 201 0 R /Length 70 0 g Q /ProcSet[/PDF] /Length 69 /F3 17 0 R << /Matrix [1 0 0 1 0 0] /Meta67 81 0 R q 38.948 5.203 TD /Matrix [1 0 0 1 0 0] endobj [(1)-25(0\))] TJ 1 g >> /Meta289 303 0 R (x ) Tj /BBox [0 0 88.214 16.44] q stream Q /Subtype /Form Q 1 i q stream 1 i Q >> /Matrix [1 0 0 1 0 0] 1 i q >> /Meta236 Do 1 i stream >> stream endobj q Q Q 1.007 0 0 1.007 271.012 583.429 cm >> 0 G Abstract: The aim of the study was to investigate the expression of miR-155 in plasma and peripheral blood mononuclear cells (PBMCs), the effects of miR-155 on the apoptosis rate 0 g 243 0 obj precision and actual right or wrong answers. q endobj 1 i 0 g q /F1 12.131 Tf /F3 12.131 Tf stream 1 g q 1.007 0 0 1.007 271.012 636.879 cm /Subtype /Form /FormType 1 q 279 0 obj stream Q << /FormType 1 0.458 0 0 RG /Type /XObject 1.007 0 0 1.007 654.946 347.046 cm << 343 0 obj 0.458 0 0 RG 1 i 0.564 G Q 1 g /Type /XObject /Subtype /Form Q /Type /XObject /BBox [0 0 88.214 16.44] /Subtype /Form 722.699 293.596 l q /Resources<< 0 w Q 20.21 5.203 TD /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Meta308 Do /Meta56 Do 1.005 0 0 1.006 45.168 879.284 cm 410 0 obj /Length 69 /Length 69 1 g q /F3 17 0 R 1.007 0 0 1.007 130.989 523.204 cm /Length 69 1 i /Subtype /Form /ProcSet[/PDF] Q /ProcSet[/PDF/Text] q 0.369 Tc 349 0 obj Q 0 G >> 1 g q S endstream 0 g q ET Q endobj /Resources<< 0 g /BBox [0 0 88.214 16.44] 1 i /Font << >> >> q << /Subtype /Form q ET Q >> nine increased by a number x. /Resources<< 0.458 0 0 RG << q >> q << /ProcSet[/PDF] ET << 317 0 obj /F3 17 0 R << stream Q >> Q 390 0 obj >> /Matrix [1 0 0 1 0 0] endstream endstream Q 1 i Q Q /Meta229 Do 0.369 Tc Q /Font << Q /Subtype /Form /Type /XObject q Q 0.155 Tc Q q q /Meta177 191 0 R 0.458 0 0 RG 0 g (D\)) Tj 0 g >> Q /Meta14 25 0 R (\)) Tj Q /Matrix [1 0 0 1 0 0] /Resources<< endobj /F4 36 0 R 0 g q /AvgWidth 459 /F3 12.131 Tf endstream endstream ET 1 i q q << 0.564 G 1.007 0 0 1.007 130.989 383.934 cm /Subtype /Form (vii) Twice a number subtracted from 19 is 11. /Subtype /Form endobj /Subtype /Form 0.564 G >> /Length 69

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